Biology part two!!=[?

1.In humans the gene for albinism(a) is recessive to the gene for normal skin a normal male marries a normal female and they have two children one is normal and the second is albino give a genotype for all the family memberes


2.In snapdragons the alleles for flower color red and white are codominant


a. if your cross a red flower w/ a white flower what will the phenotypes and genotypes be for all the offspring


b.if you cross the offspring of the example above what are the possible genotypesw and phenotypes of thier offspring


4.in dogs pink tongues(P) is dominant over black tongues(p) what will the ratios be if you cross


a.homozygous pink tongue x black tongue


b.heterozygous pink tongue x heterozygous black tounge


5.a cross between red shorthorn bull and a white shorthorn cow results in all roan offspring what are the types of offspring that would result from a cross between a white bull and roan cow


see part three.=[

Biology part two!!=[?
1. Aa A? (You can't tell which parent is which, or what the second parents second gene is with the information given)


2. RW


4a. All Pp


4b. You can't have a heterozygous dog with a black tongue according the the information given. If the black was homozygous then the ratio would be half Pp half pp.


5. Assuming the information means co-dominance... You would get half homozygous white half roan.
Reply:1. parents must both be Aa; normal child is A- (can be AA or Aa); albino child is aa


2. a)Aa


b) A genotypic ratio of 1:2:1 (AA, Aa, aa respectively) and a phenotypic ratio that is the same (1 red, 2 pink, 1 white)


4. a) All of the offspring will be the same (Pp)


b) there can be no heterozygous black tongue because black tongue is recessive.. so i dunno maybe you copied the question wrong? but if you cross the two heterozygotes (Pp x Pp) you will get a genotypic ratio of 1:2:1 and a phenotypic ratio of 3:1