Answer these questions?

STATEMENT: Color-blindness is due to a sex-linked recessive gene. A colorblind man marries a normal-visioned woman whose father is colorblind.





6. We know this colorblind man received the gene from:


a) his father; b) his mother; c) both his mother and father;


d) either his father or mother; e) mutant sperm.





7. What percentage of their daughters would be colorblind?


a) 0%; b) 1/4; c) 1/2; d) 3/4; e) 100%.





8. How many unique gametes could be produced through independent assortment by an individual with the genotype Aa Bb CC Dd EE?


a) 4; b) 8; c) 16; d) 32; e) 1/64.





9. In snapdragons, heterozygotes have pink flower, whereas homozygotes have either red or white (recessive) flowers. When plants with red flowers are crossed with plant with white flowers, what proportion of the offspring will have pink flowers?


a) zero; b) 25%; c) 50%; d) 75%; e) 100%.

Answer these questions?
Since the question states that this is a sex linked recessive we are looking at the X chromosome. If you have 2 recessive X Chromosomes or 1X recessive and a Y you would be colorblind. so


6) The man received the gene from his mom. He received an Y from his dad which cant carry this trait.


He is X+Y crossed with X+(her dad was colorblind)X-(normal vision mom had to give a dominant gene).


so cross of X+ with X+ X+X- would yield 50% of the offspring girls colorblind.


since there is 3 pairs of genotypes that differ we can say 2^3 unique gametes so 8


last one is RR x WW all offspring will be RW(pink)